Optimal. Leaf size=258 \[ \frac{64 \sqrt [4]{2} \sqrt{\frac{x^2}{\left (\sqrt{3 x^2-2}+\sqrt{2}\right )^2}} \left (\sqrt{3 x^2-2}+\sqrt{2}\right ) \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{3 x^2-2}}{\sqrt [4]{2}}\right ),\frac{1}{2}\right )}{1053 \sqrt{3} x}+\frac{2}{39} \left (3 x^2-2\right )^{3/4} x^5+\frac{40 \left (3 x^2-2\right )^{3/4} x^3}{1053}+\frac{32 \left (3 x^2-2\right )^{3/4} x}{1053}+\frac{128 \sqrt [4]{3 x^2-2} x}{1053 \left (\sqrt{3 x^2-2}+\sqrt{2}\right )}-\frac{128 \sqrt [4]{2} \sqrt{\frac{x^2}{\left (\sqrt{3 x^2-2}+\sqrt{2}\right )^2}} \left (\sqrt{3 x^2-2}+\sqrt{2}\right ) E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{3 x^2-2}}{\sqrt [4]{2}}\right )|\frac{1}{2}\right )}{1053 \sqrt{3} x} \]
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Rubi [A] time = 0.14362, antiderivative size = 258, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {321, 230, 305, 220, 1196} \[ \frac{2}{39} \left (3 x^2-2\right )^{3/4} x^5+\frac{40 \left (3 x^2-2\right )^{3/4} x^3}{1053}+\frac{32 \left (3 x^2-2\right )^{3/4} x}{1053}+\frac{128 \sqrt [4]{3 x^2-2} x}{1053 \left (\sqrt{3 x^2-2}+\sqrt{2}\right )}+\frac{64 \sqrt [4]{2} \sqrt{\frac{x^2}{\left (\sqrt{3 x^2-2}+\sqrt{2}\right )^2}} \left (\sqrt{3 x^2-2}+\sqrt{2}\right ) F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{3 x^2-2}}{\sqrt [4]{2}}\right )|\frac{1}{2}\right )}{1053 \sqrt{3} x}-\frac{128 \sqrt [4]{2} \sqrt{\frac{x^2}{\left (\sqrt{3 x^2-2}+\sqrt{2}\right )^2}} \left (\sqrt{3 x^2-2}+\sqrt{2}\right ) E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{3 x^2-2}}{\sqrt [4]{2}}\right )|\frac{1}{2}\right )}{1053 \sqrt{3} x} \]
Antiderivative was successfully verified.
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Rule 321
Rule 230
Rule 305
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int \frac{x^6}{\sqrt [4]{-2+3 x^2}} \, dx &=\frac{2}{39} x^5 \left (-2+3 x^2\right )^{3/4}+\frac{20}{39} \int \frac{x^4}{\sqrt [4]{-2+3 x^2}} \, dx\\ &=\frac{40 x^3 \left (-2+3 x^2\right )^{3/4}}{1053}+\frac{2}{39} x^5 \left (-2+3 x^2\right )^{3/4}+\frac{80}{351} \int \frac{x^2}{\sqrt [4]{-2+3 x^2}} \, dx\\ &=\frac{32 x \left (-2+3 x^2\right )^{3/4}}{1053}+\frac{40 x^3 \left (-2+3 x^2\right )^{3/4}}{1053}+\frac{2}{39} x^5 \left (-2+3 x^2\right )^{3/4}+\frac{64 \int \frac{1}{\sqrt [4]{-2+3 x^2}} \, dx}{1053}\\ &=\frac{32 x \left (-2+3 x^2\right )^{3/4}}{1053}+\frac{40 x^3 \left (-2+3 x^2\right )^{3/4}}{1053}+\frac{2}{39} x^5 \left (-2+3 x^2\right )^{3/4}+\frac{\left (64 \sqrt{\frac{2}{3}} \sqrt{x^2}\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{1+\frac{x^4}{2}}} \, dx,x,\sqrt [4]{-2+3 x^2}\right )}{1053 x}\\ &=\frac{32 x \left (-2+3 x^2\right )^{3/4}}{1053}+\frac{40 x^3 \left (-2+3 x^2\right )^{3/4}}{1053}+\frac{2}{39} x^5 \left (-2+3 x^2\right )^{3/4}+\frac{\left (128 \sqrt{x^2}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1+\frac{x^4}{2}}} \, dx,x,\sqrt [4]{-2+3 x^2}\right )}{1053 \sqrt{3} x}-\frac{\left (128 \sqrt{x^2}\right ) \operatorname{Subst}\left (\int \frac{1-\frac{x^2}{\sqrt{2}}}{\sqrt{1+\frac{x^4}{2}}} \, dx,x,\sqrt [4]{-2+3 x^2}\right )}{1053 \sqrt{3} x}\\ &=\frac{32 x \left (-2+3 x^2\right )^{3/4}}{1053}+\frac{40 x^3 \left (-2+3 x^2\right )^{3/4}}{1053}+\frac{2}{39} x^5 \left (-2+3 x^2\right )^{3/4}+\frac{128 x \sqrt [4]{-2+3 x^2}}{1053 \left (\sqrt{2}+\sqrt{-2+3 x^2}\right )}-\frac{128 \sqrt [4]{2} \sqrt{\frac{x^2}{\left (\sqrt{2}+\sqrt{-2+3 x^2}\right )^2}} \left (\sqrt{2}+\sqrt{-2+3 x^2}\right ) E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{-2+3 x^2}}{\sqrt [4]{2}}\right )|\frac{1}{2}\right )}{1053 \sqrt{3} x}+\frac{64 \sqrt [4]{2} \sqrt{\frac{x^2}{\left (\sqrt{2}+\sqrt{-2+3 x^2}\right )^2}} \left (\sqrt{2}+\sqrt{-2+3 x^2}\right ) F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{-2+3 x^2}}{\sqrt [4]{2}}\right )|\frac{1}{2}\right )}{1053 \sqrt{3} x}\\ \end{align*}
Mathematica [C] time = 0.0169025, size = 68, normalized size = 0.26 \[ \frac{2 x \left (16\ 2^{3/4} \sqrt [4]{2-3 x^2} \, _2F_1\left (\frac{1}{4},\frac{1}{2};\frac{3}{2};\frac{3 x^2}{2}\right )+81 x^6+6 x^4+8 x^2-32\right )}{1053 \sqrt [4]{3 x^2-2}} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.038, size = 65, normalized size = 0.3 \begin{align*}{\frac{2\,x \left ( 27\,{x}^{4}+20\,{x}^{2}+16 \right ) }{1053} \left ( 3\,{x}^{2}-2 \right ) ^{{\frac{3}{4}}}}+{\frac{32\,{2}^{3/4}x}{1053}\sqrt [4]{-{\it signum} \left ( -1+{\frac{3\,{x}^{2}}{2}} \right ) }{\mbox{$_2$F$_1$}({\frac{1}{4}},{\frac{1}{2}};\,{\frac{3}{2}};\,{\frac{3\,{x}^{2}}{2}})}{\frac{1}{\sqrt [4]{{\it signum} \left ( -1+{\frac{3\,{x}^{2}}{2}} \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{6}}{{\left (3 \, x^{2} - 2\right )}^{\frac{1}{4}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{x^{6}}{{\left (3 \, x^{2} - 2\right )}^{\frac{1}{4}}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 0.809982, size = 29, normalized size = 0.11 \begin{align*} \frac{2^{\frac{3}{4}} x^{7} e^{- \frac{i \pi }{4}}{{}_{2}F_{1}\left (\begin{matrix} \frac{1}{4}, \frac{7}{2} \\ \frac{9}{2} \end{matrix}\middle |{\frac{3 x^{2}}{2}} \right )}}{14} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{6}}{{\left (3 \, x^{2} - 2\right )}^{\frac{1}{4}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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